12x^2+64x+45=0

Solution for 12x^2+64x+45=0 equation:

12x^2+64x+45=0

a = 12; b = 64; c = +45;
Δ = b2-4ac
Δ = 642-4·12·45
Δ = 1936
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1936}=44$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(64)-44}{2*12}=\frac{-108}{24}
=-4+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(64)+44}{2*12}=\frac{-20}{24}
=-5/6
$